If \( f(x)=\left\{\begin{array}{cc}\frac{\sin \{\cos x\}}{x-\frac{\pi}{2}} & x \neq \frac{\pi}{2... VIDEO
If \( f(x)=\left\{\begin{array}{cc}\frac{\sin \{\cos x\}}{x-\frac{\pi}{2}} & x \neq \frac{\pi}{2} \\ 1 & x=\frac{\pi}{2}\end{array}\right. \), where \( \{k\} \) represents the fractional part of \( k \), then:
(a) \( f(x) \) is continuous at \( x=\frac{\pi}{2} \)
(b) \( \lim _{x \rightarrow \frac{\pi}{2}} f(x) \) dos not exist
(c) \( \lim _{x \rightarrow \frac{\pi}{2}} f(x) \) exists, but \( f \) is not continous at \( x=\frac{\pi}{2} \)
(d) \( \lim _{x \rightarrow \frac{\pi}{2}} f(x)=1 \)
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