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If \( f(x)=\left\{\begin{array}{ll}a \sin \frac{\pi}{2}(x+1), & x \leq 0 \\ \frac{\tan x-\sin x}{x^{3}}, & x0\end{array}\right. \) is continuous at \( x=0 \), then a equals
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{3} \)
(c) \( \frac{1}{4} \)
(d) \( \frac{1}{6} \)
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