If \( \int f(x) d x=g(x) \) then \( \int f^{-1}(x) d x \) is equal ...

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If \( \int f(x) d x=g(x) \) then \( \int f^{-1}(x) d x \) is equal to
\( \mathrm{P}^{12: 20} \)
(1) \( g^{-1}(x)+\mathrm{C} \)
W
(2) \( x f^{-1}(x)-g\left(f^{-1}(x)\right)+C \)
(3) \( x f^{-1}(x)-g^{-1}(x)+C \)
(4) \( f^{-1}(x)+C \)
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