If \( \left|z_{1}\right|=\left|z_{2}\right| \) and \( \arg \left(\frac{z_{1}}{z_{2}}\right)=\pi ...
If \( \left|z_{1}\right|=\left|z_{2}\right| \) and \( \arg \left(\frac{z_{1}}{z_{2}}\right)=\pi \), then \( z_{1}+z_{2}= \)
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