If \( S_{n}=\sum_{r=1}^{n} t_{r}=\frac{1}{6} n(n+1)(n+2) \forall n ...
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If \( S_{n}=\sum_{r=1}^{n} t_{r}=\frac{1}{6} n(n+1)(n+2) \forall n \geq 1 \), then
\( \lim _{n \rightarrow \infty} \sum_{r=1}^{n} \frac{1}{t_{r}} \) is
(a) 1
(b) \( 3 / 2 \)
(c) 2
(d) \( 5 / 2 \)
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