If sin ^2θ-5 sinθ+3/cos ^2θ=1, then θ can be (a) 30^∘ (b) 45^∘ (c) 60^∘ (d) 0^∘

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If sin ^2θ-5 sinθ+3/cos ^2θ=1, then θ can be
(a) 30^∘
(b) 45^∘
(c) 60^∘
(d) 0^∘

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