If the area of the triangle whose one vertex is the vertex of the parabola, \(y^2+4\left(x-a^2\r....

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If the area of the triangle whose one vertex is the vertex of the parabola, \(y^2+4\left(x-a^2\right)=0\) and the other two vertices are the points of intersection of the parabola and \(y\)-axis, is 250 sq. units, then a value of ' \(a\) ' is 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live




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