If the shortest wavelength of \( \mathrm{H} \)-atom in Lyman Series is \( \mathrm{X} \) then the...
Channel:
Subscribers:
449,000
Published on ● Video Link: https://www.youtube.com/watch?v=CtCJkHgtAHg
If the shortest wavelength of \( \mathrm{H} \)-atom in Lyman Series is \( \mathrm{X} \) then the longest wavelength in Balmer Series of \( \mathrm{He}+ \) is
(1) \( \frac{9 X}{5} \)
(2) \( \frac{38 X}{5} \)
(3) \( \frac{X}{4} \)
(4) \( \frac{5 X}{9} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live