If \( x^{y}=e^{x-y} \), prove that \( \frac{d y}{d x}=\frac{\log x}{(\log x e)^{2}} \)
If \( x^{y}=e^{x-y} \), prove that \( \frac{d y}{d x}=\frac{\log x}{(\log x e)^{2}} \)
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