If \( z=\frac{\sqrt{3}}{2}+\frac{i}{2} \cdot(i=\sqrt{-1}) \), then \( \left(1+i z+z^{5}+i z^{8}\...
If \( z=\frac{\sqrt{3}}{2}+\frac{i}{2} \cdot(i=\sqrt{-1}) \), then \( \left(1+i z+z^{5}+i z^{8}\right)^{9} \) is equal to
(2019 Main, 8 April II)
\( \mathrm{P} \)
(a) 1
(b) \( (-1+2 i)^{9} \)
(c) \( -1 \)
(d) 0
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