In a sequence of \( (4 n+1) \) terms the first \( (2 n+1) \) terms ...
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In a sequence of \( (4 n+1) \) terms the first \( (2 n+1) \) terms are in AP whose common difference is 2 , and the last \( (2 n+1) \) terms are in GP whose common ratio \( 0.5 \). If the middle terms of the AP and GP are equal, then
\( \mathrm{P} \)
First term of the sequence is
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(A) \( \frac{4 n+2 n \cdot 2^{n}}{2^{n}-1} \)
(B) \( \frac{4 n-2 n \cdot 2^{n}}{2^{n}-1} \)
(C) \( \frac{2 n-n \cdot 2^{n}}{2^{n}-1} \)
(D) \( \frac{2 n+n \cdot 2^{n}}{2^{n}-1} \)
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