In \( \left[\mathrm{Cr}\left(\mathrm{O}_{2}\right)\left(\mathrm{NH}_{3}\right)_{4} \mathrm{H}_{2....

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In \( \left[\mathrm{Cr}\left(\mathrm{O}_{2}\right)\left(\mathrm{NH}_{3}\right)_{4} \mathrm{H}_{2} \mathrm{O}\right] \mathrm{Cl}_{2} \), oxidation number of \( \mathrm{Cr} \) is
\( \mathrm{P} \)
+3 , then oxygen will be in the from:
(1) Dioxo
(2) Peroxo
(3) Superoxo
(4) Oxo


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