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In the figure shown, after the switch ' \( \mathrm{S} \) ' is turned from position 'A' to position 'B', the energy
\( \mathrm{P} \) dissipated in the circuit in terms of capacitance ' \( \mathrm{C} \) ' and total charge ' \( \mathrm{Q} \) ' is:
(A) \( \frac{3}{8} \frac{Q^{2}}{\mathrm{C}} \)
(B) \( \frac{5}{8} \frac{Q^{2}}{\mathrm{C}} \)
(C) \( \frac{1}{8} \frac{\mathrm{Q}^{2}}{\mathrm{C}} \)
(D) \( \frac{3}{4} \frac{Q^{2}}{\mathrm{C}} \)
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