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In the reaction, \( 2 \mathrm{KClO}_{3} \rightarrow 2 \mathrm{KCl}+3 \mathrm{O}_{2} \) when \( 36.75 \mathrm{~g} \) of \( \mathrm{KClO}_{3} \) is heated, the volume of oxygen evolved at N.T.P. will be :
\( \mathrm{P} \)
(A) \( 9.74 \mathrm{dm}^{3} \)
(B) \( 8.92 \mathrm{dm}^{3} \)
(C) \( 10.08 \mathrm{dm}^{3} \)
(D) \( 22.4 \mathrm{dm}^{3} \)
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