Initially the capacitor is charged to a potential of \( 5 V \) and ...
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Initially the capacitor is charged to a potential of \( 5 V \) and then connected to position 1 with the shown polarity for \( 1 \mathrm{~s} \). After 1s, it is connected across the inductor at position 2.
\( \mathrm{P} \)
\( \mathrm{W} \)
The potential difference across the capacitor after \( 1 \mathrm{~s} \) of its connection to position 1 is
(a) \( 5\left[2+\frac{1}{e}\right] \mathrm{V} \)
(b) \( 5\left[2-\frac{1}{e}\right] \mathrm{V} \)
(c) \( 5\left[1+\frac{2}{e}\right] \mathrm{V} \)
(d) None of these
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