It is given that \( \triangle \mathrm{ABC} \sim \triangle \mathrm{PQR} \) with \( \frac{\mathrm{... VIDEO
It is given that \( \triangle \mathrm{ABC} \sim \triangle \mathrm{PQR} \) with \( \frac{\mathrm{BC}}{\mathrm{QR}}=\frac{1}{3} \). Then \( \frac{\operatorname{ar}(\triangle \mathrm{PRQ})}{\operatorname{ar}(\triangle \mathrm{BCA})} \) is equal tohttps://bit.ly/YTAI_PWAP https://www.pw.live
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