Largest Positive Integer That Exists With Its Negative |4 Approaches|Leetcode 2441 |codestorywithMIK
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Problem Name : Largest Positive Integer That Exists With Its Negative | 4 Detailed Approaches | Leetcode 2441 | codestorywithMIK
Company Tags : Microsoft
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Leetcode%20Easy/Largest%20Positive%20Integer%20That%20Exists%20With%20Its%20Negative.cpp
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Summary :
Here's a summary of each approach:
1. **Approach-1 (Nested Loops):**
- **Time Complexity (T.C):** \( O(n^2) \) where \( n \) is the size of the input array `nums`.
- **Space Complexity (S.C):** \( O(1) \).
- This approach iterates through the array twice to find pairs where one element is the negative of the other. It updates the maximum accordingly.
2. **Approach-2 (Sorting + 2-Pointers):**
- **T.C:** \( O(n) \) due to the sorting operation.
- **S.C:** \( O(1) \).
- It sorts the array and then uses two pointers to traverse the sorted array to find pairs where one element is the negative of the other.
3. **Approach-3 (Using Set):**
- **T.C:** \( O(n) \) where \( n \) is the size of the input array `nums`.
- **S.C:** \( O(n) \) due to the use of a set to store seen numbers.
- This approach utilizes a set to store seen numbers and iterates through the array. It checks if the negation of the current number exists in the set.
4. **Approach-4 (Using Array as Index):**
- **T.C:** \( O(n) \) where \( n \) is the size of the input array `nums`.
- **S.C:** \( O(1) \) as it uses a fixed-size array.
- It uses an array to mark seen numbers and iterates through the input array `nums`. If the negation of the current number exists in the array, it updates the result accordingly.
Each approach has its own trade-offs in terms of time and space complexity. Depending on the characteristics of the input data and the constraints, one approach may be more suitable than the others.
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✨ Timelines✨
00:00 - Introduction
01:18 - Approach-1 (Brute Force)
04:38 - Approach-2 (Sorting + 2-Pointer)
09:37 - Approach-3 (Using hashset)
12:24 - Approach-4 (Using nums[i] as index)
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