Let \( \alpha \) be an integer such that \( \lim _{x \rightarrow 7} \frac{18-[1-x]}{[x-3 \alpha]...

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Let \( \alpha \) be an integer such that \( \lim _{x \rightarrow 7} \frac{18-[1-x]}{[x-3 \alpha]} \) exists, where \( [t] \) is greatest integer \( \leq t \). Then \( \alpha \) is equal to
(a) -6
(b) -2
(c) 2
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