Let \( f(x)=f_{1}(x)-2 f_{2}(x) \), where
\[
\begin{aligned}
f_{1}(...
Let \( f(x)=f_{1}(x)-2 f_{2}(x) \), where
\[
\begin{aligned}
f_{1}(x)=\left\{\begin{array}{ll}
\min \left\{x^{2},|x|\right\}, & |x| \leq 1 \\
\max \left\{x^{2},|x|\right\}, & |x|1
\end{array}\right. \\
\text { and } f_{2}(x)=\left\{\begin{array}{ll}
\min \left\{x^{2},|x|\right\}, & |x|1 \\
\max \left\{x^{2},|x|\right\}, & |x| \leq 1
\end{array}\right. \\
\text { let } g(x)=\left\{\begin{array}{ll}
\min \{f(t), & -3 \leq t \leq x,-3 \leq x0\} \\
\max \{f(t), & 0 \leq tx, 0 \leq x \leq 3\} .
\end{array}\right.
\end{aligned}
\]
P
W
The graph of \( y=g(x) \) in its domain is broken at
(a) 1 point
(b) 2 points
(c) 3 points
(d) None of these
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