Let y = y(x) be the solution of the differential equation dydx=(y+1)(y+1)ex2/2-x,0<x<.... VIDEO
Let y = y(x) be the solution of the differential equation dydx=(y+1)(y+1)ex2/2-x,0<x<2.1 with y(2)=0. Then the value of dydx at x = 1 is equal to: š²PW App Link - https://bit.ly/YTAI_PWAP šPW Website - https://www.pw.live
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