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Let \( y=y(x) \) be the solution of the differential equation,
\( P \) \( \left(x^{2}+1\right)^{2} \frac{d y}{d x}+2 x\left(x^{2}+1\right) y=1 \) such that \( y(0)=0 \). If

W)
\( \sqrt{a} y(1)=\frac{\pi}{32} \), then the value of ' \( a \) ' is :
[JEE Main - 2019(April)]
(a) \( \frac{1}{2} \)
(b) \( \frac{1}{16} \)
(c) \( \frac{1}{4} \)
(d) 1
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