Numericals based on Lens Formula - Light: Reflection And Refraction | Class 10 Physics 2022-23

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Published on September 8, 2020 7:15:11 AM ● Video Link: https://www.youtube.com/watch?v=iM5EZMZvOCQ

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✅ In this video,

✔️ Class: 6th
✔️ Subject: Physics
✔️ Chapter: Light: Reflection And Refraction (Chapter 10)
✔️ Topic Name: Numerical Based on Lens Formula - Light: Reflection And Refraction | Class 10 Physics Chapter 10 (2022-23)
✔️ Topics Covered In This Video (by Vibhuti Ma'am): This Youtube video provides an overview of Class 10 Science Numerical based on Lens Formula and Light: Reflection and Refraction for students preparing for their Class 10 Physics exams in 2022-23. The video is hosted by Vibhuti Mam, an experienced Physics teacher, and provides an in-depth explanation of the concepts, equations and models related to this chapter of Class 10 Physics. The video helps students to understand the principles of light and its characteristics, such as refraction, reflection and the usage of lenses, so they can master this difficult topic. It is an excellent resource for students to review the concepts taught in class and to ready themselves for their upcoming exams.
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00:00 Introduction: Light: Reflection And Refraction
00:04 Numerical Based on Lens Formula
35:39 Website Overview
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Points covered in this video:-

Lens Formula -
- An equation which represents the relation between focal length (f) of a lens, object distance (u) and image distance (v) is called lens formula.
- A convex lens may form a real image or a virtual image, depending on the position of the object.
- A concave lens forms a virtual image, wherever the object may be.
- The lens formula in all the cases is the same, and can be written as

Question. An object is placed at a distance of 30 cm from a concave lens of a focal length 15 cm. Find the nature and position of the image.
Solution. Here,
u = -30 cm
f = -15 cm
v = ?
As 1/v - 1/u = 1/f or 1/v = -1/15 -1/30 = -3/30
v = -30/3 = -10.0 cm
As v is negative, the image must be virtual and erect.

Question. Rohit focussed the image of a candle flame on a white screen using a convex lens. He notes position of candle = 26.0 cm, position of convex lens = 50.0 cm and position of screen = 74.0 cm.
What is focal length of convex lens?
Where will the image be formed if he shifts the candle towards the lens at a position of 38 cm?
Draw a ray diagram to show the formation of image in (b) above.
Solution. (a) Here,
u = distance of candle from convex lens = - (50.0 - 26.0) = -24.0 cm
v = distance of screen from convex lens = (74.0 - 50.0) = 24.0 cm

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