Power of Two | Multiple Approaches | Leetcode 231
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This is the 21st Video of our Playlist "Leetcode Easy".
We will be solving "Power of Two | Multiple Approaches | Leetcode 231" using multiple approaches.
Problem Name : Power of Two | Leetcode 231
Company Tags : GOOGLE, ADOBE
My solutions on Github : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Bit_Magic/Leetcode%20Easy/Power%20of%20Two.cpp
Leetcode Link : https://leetcode.com/problems/power-of-two/description/
Approach Summary :
Approach-1 (Using normal division):
Time Complexity (T.C): O(log(n))
Space Complexity (S.C): O(1)
Recursively checks if the given number is a power of two by repeatedly dividing it by 2 until it reaches 1.
Approach-2 (Using bit magic):
Time Complexity (T.C): O(1)
Space Complexity (S.C): O(1)
Utilizes bitwise operations to efficiently check if the given number is a power of two. It ensures that only one bit is set in the binary representation.
Approach-3 (__builtin_popcount):
Time Complexity (T.C): O(1)
Space Complexity (S.C): O(1)
Takes advantage of the Integer.bitCount method in Java, which counts the number of set bits (1s) in the binary representation. It checks if exactly one bit is set, indicating a power of two.
My Recursion Concepts Playlist : https://www.youtube.com/watch?v=pfb1Zduesi8&list=PLpIkg8OmuX-IBcXsfITH5ql0Lqci1MYPM
My DP Concepts Playlist : https://youtu.be/7eLMOE1jnls
My Graph Concepts Playlist : https://youtu.be/5JGiZnr6B5w
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Interview_DS_Algo
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Timelines : ⏰
00:00 - Problem Explanation
01:30 - Approach-1 (simple division)
03:10 - Approach-2 (Bit Magic)
05:38 - Approach-3 (Using built-in function)
08:18 - Approach-4 (Bhai Bhai Bhai Approach)
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