Selected Math Puzzle Problem #62. [HD]

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A second way to play roulette is to bet on red or black. Suppose a player bets $1 on red. If the ball stops on a red number (18 of them), the player receives twice his or her stake; in this case, the player wins $1. If a black number comes up, the player loses his or her stake. If a 0 or 00 turns up, then the wheel is spun again until it stops on a number different from 0 and 00. If this is black, the player closes the $1, but if it red, the player receives only his or her original stake (gaining nothing).
a. What is the expected value of this game?
b. If you bet $0.50 on red and $0.50 on black, what is the expected value of the game?


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