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The amount of heat required to convert \( 5 \mathrm{~g} \) of ice at
\( \mathrm{P} \) \( 0^{\circ} \mathrm{C} \) into water at \( 40^{\circ} \mathrm{C} \) is (Take latent heat of fusion
\( \mathrm{W} \)
\( =80 \mathrm{cal} / \mathrm{g} \), specific heat of water \( =1 \mathrm{cal} / \mathrm{g}-{ }^{\circ} \mathrm{C} \) ) :
(1) \( 400 \mathrm{cal} \)
(2) \( 200 \mathrm{cal} \)
(3) \( 600 \mathrm{cal} \)
(4) \( 1000 \mathrm{cal} \)
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