The binding energy of \( \alpha \)-particle \( { }_{2}^{4} \mathrm{He} \) is \( 7.047 \mathrm{Me....

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Question The binding energy of \( \alpha \)-particle \( { }_{2}^{4} \mathrm{He} \) is \( 7.047 \mathrm{MeV} \) per nucleon and the binding energy of deutron \( { }_{1}^{2} H \) is \( 1.112 \mathrm{MeV} \) per nucleon. Then in the fusion reaction \( { }_{1}^{2} H+{ }_{1}^{2} H \rightarrow{ }_{2}^{4} H e+Q \), the energy \( Q \) released is
(A) \( 23.74 \mathrm{MeV} \)
(B) \( 32.82 \mathrm{MeV} \)
(C) \( 11.9 \mathrm{MeV} \)
(D) \( 4.94 \mathrm{MeV} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live



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