The diagram shows a circuit with two identical resistors. The battery has a negligible internal resistance. What will the effect on the ammeter and voltmeter be if the switch \( S \) is closed?
\begin{tabular}{|c|l|c|l|}
\hline \multicolumn{2}{|c|}{ Column-I } & \multicolumn{2}{c|}{ Column-II } \\
\hline A. & Ammeter reading & p. & Increases \\
\hline B. & Voltmeter reading & q. & Decreases \\
\hline C. & \( \begin{array}{l}\text { Equivalent resistance } \\
\text { of circuit }\end{array} \) & r. & Does not change \\
\hline D. & \( \begin{array}{l}\text { Power dissipated } \\
\text { across } \text { R in right } \\
\text { branch. }\end{array} \) & s. & Becomes zero \\
\hline
\end{tabular}
(a) A-(s, p); B-(q); C-(p); D-(q)
(b) A-(p); B-(p); C-(p); D-(q)
(c) A-(p); B-(p); C-(q); D-(s, q)
(d) \( \mathrm{A}-(\mathrm{s}) ; \mathrm{B}-(\mathrm{q}, \mathrm{r}) ; \mathrm{C}-(\mathrm{p}) ; \mathrm{D}-(\mathrm{r}) \)
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