Duration: 4:14

3 views

0

The energy of a particle executing simple harmonic motion is given by \( \mathrm{E}=\mathrm{Ax}^{2}+\mathrm{Bv}^{2} \), where
\( P \) \( \mathrm{x} \) is the displacement from mean position \( \mathrm{x}=0 \)

W and \( v \) is the velocity of the particle at \( x \) then choose the INCORRECT statement.
(1) Amplitude of SHM is \( \sqrt{\frac{2 E}{A}} \)
(2) Maximum velocity of the particle during SHM is \( \sqrt{\frac{E}{B}} \)
(3) Time period of motion is \( 2 \pi \sqrt{\frac{\mathrm{B}}{\mathrm{A}}} \)
(4) Maximum acceleration of particle is
\[
-\frac{1}{\mathrm{~B}} \sqrt{\frac{\mathrm{EA}}{1}}
\]
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live