The energy of \( \mathrm{H} \)-atom in \( \mathrm{n}^{\text {th }} \) orbit is \( \mathrm{E}_{\m...
The energy of \( \mathrm{H} \)-atom in \( \mathrm{n}^{\text {th }} \) orbit is \( \mathrm{E}_{\mathrm{n}} \), then energy in \( \mathrm{n}^{\text {th }} \) orbit of singly ionised helium ion will be:-
(1) \( 4 E_{n} \)
(2) \( \mathrm{E}_{\mathrm{n}} / 4 \)
(3) \( 2 E_{n} \)
(4) \( \mathrm{E}_{\mathrm{n}} / 2 \)
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