The equation \( \cos ^{2} x-\sin x+\lambda=0, x \in(0, \pi / 2) \) ... VIDEO
The equation \( \cos ^{2} x-\sin x+\lambda=0, x \in(0, \pi / 2) \) has roots then value(s) of \( \lambda \) can be equal to :
(a) 0
(b) -1
(c) \( 1 / 2 \)
(d) 1
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