The given figure represents the phasor diagram of a series LCR circuit connected to an ac source....
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The given figure represents the phasor diagram of a series LCR circuit connected to an ac source. At the instant \( \mathrm{t}^{\prime} \) when the source voltage is given by \( \mathrm{V}= \) \( \mathrm{V}_{0} \cos \omega \mathrm{t} \), the current in the circuit will be
(1) \( I=I_{0} \cos \left(\omega t^{\prime}+\pi / 6\right) \)
(2) \( I=I_{0} \cos \left(\omega t^{\prime}-\pi / 6\right) \)
(3) \( I=I_{0} \cos \left(\omega t^{\prime}+\pi / 3\right) \)
(4) \( I=I_{0} \cos \left(\omega t^{\prime}-\pi / 3\right) \)
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