The imaginary angular velocity of the earth for which the effective acceleration due to gravity ...

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The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to
[AMU (Med.) 2012]
(a) \( 1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(b) \( 2.50 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(c) \( 3.75 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(d) \( 5.0 \times 10^{-3} \mathrm{rad} / \mathrm{s} \)
(Take \( g=10 \mathrm{~m} / \mathrm{s}^{2} \) for the acceleration due to gravity if the earth were at rest and radius of earth equal to \( 6400 \mathrm{~km} \).)
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