The length of a wire of a potentiometer is \( 100 \mathrm{~cm} \), and the emf of its stand and ...
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The length of a wire of a potentiometer is \( 100 \mathrm{~cm} \), and the emf of its stand and cell is \( E \) volt. It is employed to measure the emf of a battery whose internal resistance is \( 0.5 \Omega \). If the balance point is obtained at \( l=30 \mathrm{~cm} \) from the positive end, the emf of the battery is
(A) \( \frac{30 E}{100.5} \)
(B) \( \frac{30 E}{100-0.5} \)
(C) \( \frac{30(E-0.5 i)}{100} \), where \( i \) is the current in the potentiometer wire
(D) \( \frac{30 E}{100} \)
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