The length of \( n^{\text {th }} \) seconds pendulum on the surface of Earth is \( 1 \mathrm{~m}...

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The length of \( n^{\text {th }} \) seconds pendulum on the surface of Earth is \( 1 \mathrm{~m} \). Its length on the surface of Moon, where \( g \) is \( 1 / 6^{\text {th }} \) the value of \( g \) on the surface of Earth, is
\( P \)
(A) \( 1 / 6 \mathrm{~m} \)
(B) \( 6 \mathrm{~m} \)
(C) \( 1 / 36 \mathrm{~m} \)
(D) \( 36 \mathrm{~m} \).
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