The magnetic field vector of an electromagnetic wave is given by B=B0i^+j^2cos(kz-ωt) ....

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The magnetic field vector of an electromagnetic wave is given by B=B0i^+j^2cos(kz-ωt) where i^,j^ represents unit vector along x and y-axis respectively. At t = 0s, two electric charges q1 of 4π coulomb and q2 of 2π coulomb located at 0,0,πk and 0,0,3πk respectively, have the same velocity of 0.5ci^ (where c is the velocity of light). The ratio of the force acting on charge q1 to q2 is : ๐Ÿ“ฒPW App Link - https://bit.ly/YTAI_PWAP ๐ŸŒPW Website - https://www.pw.live



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