The \( \mathrm{E}^{\circ} \) at \( 25^{\circ} \mathrm{C} \) for the following reaction is \( 0.2....

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Question The \( \mathrm{E}^{\circ} \) at \( 25^{\circ} \mathrm{C} \) for the following reaction is \( 0.22 \mathrm{~V} \). Calculate the equilibrium constant at \( 25^{\circ} \mathrm{C} \). \( \mathrm{H}_{2}(\mathrm{~g})+2 \mathrm{AgCl}(\mathrm{s}) \rightarrow 2 \mathrm{Ag}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \)
(A) \( 2.8 \times 10^{7} \)
(B) \( 5.2 \times 10^{8} \)
(C)  \( 5.2 \times 10^{6} \)
(D) \( 5.2 \times 10^{3} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live



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