The equilibrium constant for the following general reaction is \( 10^{30} \). Calculate \( \math....
Channel:
Subscribers:
451,000
Published on ● Video Link: https://www.youtube.com/watch?v=BBoHEYRqVTc
Question The equilibrium constant for the following general reaction is \( 10^{30} \). Calculate \( \mathrm{E}^{\circ} \) for the cell at \( 298 \mathrm{~K} \). \( 2 \mathrm{X}_{2}(\mathrm{~s})+3 \mathrm{Y}^{2+}(\mathrm{aq}) \rightleftharpoons 2 \mathrm{X}_{2}^{3+}(\mathrm{aq})+3 \mathrm{Y}(\mathrm{s}) \)
(A) \( +0.105 \mathrm{~V} \)
(B) \( +0.2955 \mathrm{~V} \)
(C) \( 0.0985 \mathrm{~V} \)
(D) \( -0.2955 \mathrm{~V} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live