The number of moles of \( \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-} \)...

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The number of moles of \( \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-} \) needed to oxidize
P 0.136 equivalent of \( \mathrm{N}_{2} \mathrm{H}_{5}^{+} \)through the reaction

W \( \mathrm{N}_{2} \mathrm{H}_{5}^{+}+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} \rightarrow \mathrm{N}_{2}+\mathrm{Cr}^{3+}+\mathrm{H}_{2} \mathrm{O} \) is
(1) 0.023
(2) 0.091
(3) 0.136
(4) 0.816
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