Duration: 2:32

5 views

1

The potential energy of a particle of mass \( 2 \mathrm{~kg} \), moving along the \( x \)-axis is given by \( U(x)=16\left(x^{2}-2 x\right) J \), where \( x \) is in metres. Its speed at \( x=1 \mathrm{~m} \) is \( 2 \mathrm{~ms}^{-1} \) :
(A) The notion of the particle is uniformly accelerated
(B) The motion of the particle is oscillatory from \( x=0.5 \mathrm{~m} \) to \( x=1.5 \mathrm{~m} \)
(C) The motion of the particle is simple harmonic
(D) The period of oscillation of the particle is \( \pi / 2 \mathrm{~s} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live