The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two ste...

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The reaction of ozone with oxygen atoms
in the presence of chlorine atoms can occur
by a two step process shown below:
\(\)\mathrm { O } _ { 3 } ( \mathrm { g } ) + \mathrm { Cl } ^ { \bullet } ( \mathrm { g } ) \rightarrow \mathrm { O } _ { 2 } ( \mathrm { g } ) +\(\) \(\)\qquad \mathrm { ClO } ^ { \bullet } ( \mathrm { g } ) ....... (i)\(\)
\(\)\mathbf{k} _ {\mathrm{ i }} = 5.2 \times 10 ^ { 9 } \mathrm { L } \mathrm { mol } ^ { - 1 } \mathrm { s } ^ { - 1 }\(\)
\(\)\mathrm { ClO } ^ { \bullet } ( \mathrm { g } ) + \mathrm { O } ^ { \bullet } ( \mathrm { g } ) \rightarrow \mathrm { O } _ { 2 } ( \mathrm { g } ) + \(\) \(\)\qquad\mathrm { Cl } ^ { \bullet } ( \mathrm { g } ) ......(ii)\(\)
\(\)\mathbf { k } _ {\mathrm{ i i} } = 2.6 \times 10 ^ { 10 } \mathrm { L } \mathrm { mol } ^ { - 1 } \mathrm { s } ^ { - 1 }\(\)
The closest rate constant for the overall
reaction \(\mathrm { O } _ { 3 } ( \mathrm { g } ) + \mathrm { O } ^ { \bullet } ( \mathrm { g } ) \rightarrow 2 \mathrm { O } _ { 2 } ( \mathrm { g } )\) is :
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