The value of equilibrium constant of the reaction, \( \mathrm{HI}_{... VIDEO
The value of equilibrium constant of the reaction, \( \mathrm{HI}_{(g)} \rightleftharpoons \frac{1}{2} \mathrm{H}_{2(g)}+\frac{1}{2} \mathrm{I}_{2(g)} \)
\( \mathrm{P} \) is 8.0. The equilibrium constant of the reaction
W \( \mathrm{H}_{2(g)}+\mathrm{I}_{2(g)} \rightleftharpoons 2 \mathrm{HI}_{(g)} \) will be
(a) 16
(b) \( 1 / 8 \)
(c) \( 1 / 16 \)
(d) \( 1 / 64 \)
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