The velocity at the maximum height of a projectile is \( \mathrm{P}...
Channel:
Subscribers:
449,000
Published on ● Video Link: https://www.youtube.com/watch?v=zho44B3Mrhs
The velocity at the maximum height of a projectile is
\( \mathrm{P} \) \( \frac{\sqrt{3}}{2} \) times its initial velocity of projection \( (u) \). Its range
W on the horizontal plane is
(1) \( \frac{\sqrt{3} u^{2}}{2 g} \)
(2) \( \frac{3 u^{2}}{2 g} \)
(3) \( \frac{3 u^{2}}{g} \)
(4) \( \frac{u^{2}}{2 g} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw