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The work done in increasing the size of a soap film from \( 10 \mathrm{~cm} \times 6 \mathrm{~cm} \) to \( 10 \mathrm{~cm} \times 11 \mathrm{~cm} \) is \( 3 \times 10^{-4} \mathrm{~J} \). The surface tension of the film is
(a) \( 11 \times 10^{-2} \mathrm{~N} / \mathrm{m} \)
(b) \( 6 \times 10^{-2} \mathrm{~N} / \mathrm{m} \)
(c) \( 3 \times 10^{-2} \mathrm{~N} / \mathrm{m} \)
(d) \( 1.5 \times 10^{-2} \mathrm{~N} / \mathrm{m} \)
\( \mathrm{P} \)
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