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Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant \( \mathrm{k} \) as shown. \( \mathrm{Q}_{1} \) and \( \mathrm{Q}_{2} \) are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are \( Q_{1}{ }_{1} \) and \( Q_{2} \). Then
\( P \)
(A) \( \frac{\mathrm{Q}_{1}^{\prime}}{\mathrm{Q}_{1}}=\frac{\mathrm{k}+1}{\mathrm{k}} \)
(B) \( \frac{\mathrm{Q}_{2}^{\prime}}{\mathrm{Q}_{2}}=\frac{\mathrm{k}+1}{2} \)
(C) \( \frac{\mathrm{Q}_{2}^{\prime}}{\mathrm{Q}_{2}}=\frac{\mathrm{k}+1}{2 \mathrm{k}} \)
(D) \( \frac{\mathrm{Q}_{1}^{\prime}}{\mathrm{Q}_{1}}=\frac{\mathrm{k}}{2} \)
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