Duration: 7:25

20 views

0

Two long current carrying thin wires, both with current \( I \), are held by insulating threads of length \( L \) and are in equilibrium as shown in the figure, with threads making an angle \( \theta \) with the vertical. If wires have mass \( \lambda \) per unit length then, the value of \( I \) is \( (g= \) gravitational acceleration)
A \( \sin \theta \sqrt{\frac{\pi \lambda g L}{\mu_{0} \cos \theta}} \)
B \( 2 \sin \theta \sqrt{\frac{\pi \lambda g L}{\mu_{0} \cos \theta}} \)
C \( 2 \sqrt{\frac{\pi g L}{\mu_{0}} \tan \theta} \)
D \( \sqrt{\frac{\pi \lambda g L}{\mu_{0}} \tan \theta} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live