Two radioactive substances \( A \) and \( B \) have decay constants such that \( \lambda_{A}=2 \....
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0Question Two radioactive substances \( A \) and \( B \) have decay constants such that \( \lambda_{A}=2 \lambda_{B} \). At \( t=0 \), number of nuclei of \( B \) is twice of that of \( \mathrm{A} \). Then after what time, the ratio of number of nuclei of \( A \) to that of number of nuclei of \( B \) is \( \frac{1}{2 e} \) ?
(A) \( \frac{1}{2 \lambda_{B}} \)
(B) \( \frac{1}{\lambda_{A}} \)
(C) \( \frac{2}{\lambda_{B}} \)
(D) \( \frac{2}{\lambda_{A}} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live