What volume of \( \mathrm{O}_{2} \) measured at standard conditions will be formed by the action...
What volume of \( \mathrm{O}_{2} \) measured at standard conditions will be formed by the action of \( 100 \mathrm{~mL} \) of \( 0.5 \mathrm{~N} \mathrm{KMnO} \mathrm{O}_{4} \) on hydrogen peroxide in an acidic solution? The skeleton equation for the reaction is, \( \mathrm{KMnO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{KHSO}_{4} \)
\[
+\mathrm{MnSO}_{4}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}:
\]
(A) \( 0.12 \) litte
(B) \( 0.28 \) littee
(C) \( 0.56 \) lite
(D) \( 1.12 \) litre
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