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When it is raining vertically down, to a man walking on road the velocity of rain appears to be 1.5 times his
\( \mathrm{P} \)
velocity. To protect himself from rain he should hold
W
the umbrella at an angle \( \theta \) to vertical. Then \( \tan \theta= \)
(1) \( \frac{2}{\sqrt{5}} \)
(2) \( \frac{\sqrt{5}}{2} \)
(3) \( \frac{2}{3} \)
(4) \( \frac{3}{2} \)
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