Why does command substitution change the behaviour of a name referenced parameter of a function?
Why does command substitution change the behaviour of a name referenced parameter of a function?
I hope you found a solution that worked for you :)
The Content is licensed under (https://meta.stackexchange.com/help/licensing) CC BY-SA.
Attention! This video does always use the same license as the source!
Thanks to all those great people for their contributions!
(stackoverflow.com/users/7277667/ding-liu)Ding Liu
(stackoverflow.com/posts/79238820/revisions)glenn jackman
(stackoverflow.com/users/1745001/ed-morton)Ed Morton
(stackoverflow.com/users/2125671/philippe)Philippe
A special thanks goes out to the (stackoverflow.com/questions/79238799/why-does-command-substitution-change-the-behaviour-of-a-name-referenced-paramete)Stackexchange community
I wish you all a wonderful day! Stay safe :)
If anything is off, please write me at peter D.O.T schneider A.T ois42.de
bash shell