\( 1 \mathrm{~mL} \) of \( 0.1 \mathrm{~N} \mathrm{HCl} \) is added...
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\( 1 \mathrm{~mL} \) of \( 0.1 \mathrm{~N} \mathrm{HCl} \) is added to \( 999 \mathrm{~mL} \) solution of
P \( \mathrm{NaCl} \). The \( \mathrm{pH} \) of the resulting solution will be:
W
(1) 4
(2) 7
(3) 2
(4) 1
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